20b^2-128b+140=0

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Solution for 20b^2-128b+140=0 equation:


Simplifying
20b2 + -128b + 140 = 0

Reorder the terms:
140 + -128b + 20b2 = 0

Solving
140 + -128b + 20b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '4'.
4(35 + -32b + 5b2) = 0

Factor a trinomial.
4((7 + -5b)(5 + -1b)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(7 + -5b)' equal to zero and attempt to solve: Simplifying 7 + -5b = 0 Solving 7 + -5b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -5b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -5b = 0 + -7 -5b = 0 + -7 Combine like terms: 0 + -7 = -7 -5b = -7 Divide each side by '-5'. b = 1.4 Simplifying b = 1.4

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {1.4, 5}

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